3m^2-20m-32=0

Solution for 3m^2-20m-32=0 equation:

3m^2-20m-32=0

a = 3; b = -20; c = -32;
Δ = b2-4ac
Δ = -202-4·3·(-32)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*3}=\frac{-8}{6}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*3}=\frac{48}{6}
=8
$